Hi. I don't know the answer to this one, could someone check my reasoning and working please?

Simplify $\displaystyle \frac{2a^-2}{a^\frac{-3}{2}}$

Working on the denominator only

$\displaystyle \frac{1}{-\sqrt{a}*-\sqrt{a}*-\sqrt{a}}$

Denominator is $\displaystyle \frac{1}{a\sqrt{a}}$

So I now have $\displaystyle \frac{2a^-2}{1}*\frac{a\sqrt{a}}{1}$

Then $\displaystyle \frac{1}{2a^2}*a\sqrt{a}$

Which gives me my answer $\displaystyle \frac{a\sqrt{a}}{2a^2}$