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Math Help - Interesting Algebra Problem

  1. #1
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    Interesting Algebra Problem

    Hey Everyone,

    I am unsure how to solve the following problem, could you please show me how it's done so that I can solve similar problems in the future?

    Melissa bought a new car with 12 optional features to the car. Each optional feature costs either $23.99 or $120.84. If she paid $675.28 for all the optional features, how many of each type did she buy?

    Thanks in advance!
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  2. #2
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    let no of optional feature cost $23.99 = x
    and no of optional feature cost $120.84 =y

    therefore according to question

    x+y=12 ..........(1)
    23.99x + 120.84y = 675.28 ..........(2)
    now continue........
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  3. #3
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    Quote Originally Posted by ramiee2010 View Post
    let no of optional feature cost $23.99 = x
    and no of optional feature cost $120.84 =y

    therefore according to question

    x+y=12 ..........(1)
    23.99x + 120.84y = 675.28 ..........(2)
    now continue........
    I still don't know, I'm used to having only one variable..not two.
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  4. #4
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    Quote Originally Posted by ElectroNerd View Post
    I still don't know, I'm used to having only one variable..not two.
    for only one variable,


    let no of optional feature cost $23.99 = x
    therefore no of optional feature cost $120.84 =(12-x)
    (because total no. of options are 12)

    23.99x + 120.84(12-x) = 675.28 .................(1)
    (Melissa paid = total for optional feature cost $23.99 +total for optional feature cost $120.84)
    now solve for x
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  5. #5
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    Ok, x=8

    Thanks!
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