x = -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8
y = 3, 4, 5, 6, 7, 8
Minimum x^2 + y^2 = 0^2 + 3^2 = 9
Maximum (x + y) / y = (8 + 3) / 3 = 11/3
Both EVIDENT; is there more to your question?
Given and are integeres such that and 3 equals to or less than y and y is equal to or less than 8, find
a) the smallest possible value of ,
b) the largest possible value of over .
I appreciate your toil and kindness wholly. May God bless to you who solve my doubts.