# Math Help - Logarithm Help: Solve for x.

1. ## Logarithm Help: Solve for x.

I need to solve for x.

8^(log_2(x)) - 25^(log_5(x)) = 4x - 4

please can someone tell me how to solve this. All i have managed to do is prove it....but not solve for it.

2. Originally Posted by lockdout
I need to solve for x.

8^(log_2(x)) - 25^(log_5(x)) = 4x - 4

please can someone tell me how to solve this. All i have managed to do is prove it....but not solve for it.
ok

$A^{log_A (x) } = x$ you should know this ok

$8^{\log _2 x} - 25^{\log _5 x} = 4x-4$

$8=2^3 , 25 = 5^2$ so

$2^{(3\log _2 x )} - 5^{(2\log _5 x)} = 4x-4$

$\left(2^{\log _2 x}\right)^3 - \left(5^{\log _5 x}\right)^2 =4x-4$

$x^3 - x^2 = 4x-4$

$x^3-x^2 -4x+4 = 0$ this for you