I need to solve for x.
8^(log_2(x)) - 25^(log_5(x)) = 4x - 4
please can someone tell me how to solve this. All i have managed to do is prove it....but not solve for it.
ok
$\displaystyle A^{log_A (x) } = x $ you should know this ok
$\displaystyle 8^{\log _2 x} - 25^{\log _5 x} = 4x-4$
$\displaystyle 8=2^3 , 25 = 5^2 $ so
$\displaystyle 2^{(3\log _2 x )} - 5^{(2\log _5 x)} = 4x-4 $
$\displaystyle \left(2^{\log _2 x}\right)^3 - \left(5^{\log _5 x}\right)^2 =4x-4 $
$\displaystyle x^3 - x^2 = 4x-4 $
$\displaystyle x^3-x^2 -4x+4 = 0$ this for you