Hello, anshulbshah!
I expanded it, then repeatedly factored "by grouping".
If there is a more direct way, I hope someone finds it.
Factor: .
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Answer: .
Hello anshulbshahHaving seen Soroban's answer, I suppose this is being wise after the event, but here's a quicker method, if you spot it!
If we put in the expression, we get:
so is a factor.
Similarly and are also factors.
Since the expression is of degree in , the remaining factor is linear, and by symmetry is therefore for some constant .
So
Compare coefficients of, say, (taking the from the first factor, the from the second, the from the third and the from the fourth)
Or did I cheat a bit?
Grandad