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Math Help - Complex Numbers- Imaginary numbers

  1. #1
    DRF4590
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    Complex Numbers- Imaginary numbers


    10+i over 4-i
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  2. #2
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    Quote Originally Posted by DRF4590 View Post
    10+i over 4-i
    First do this: \frac{10+i}{4-i}=\frac{(10+i)(4+i)}{(4-i)(4+i)}=\frac{40+14i+i^2}{16-i^2}

    Then simplify: \frac{40+14i-1}{16-(-1)}

    Finally: \frac{14i+39}{17}

    But check my arithmetic...
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  3. #3
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    Quote Originally Posted by DRF4590 View Post
    10+i over 4-i
    Code:
     
    10+i      4+i
    ----- * ------
    4 - i     4+i
     
            = (10*4+i*i)+(10*i+4*i)
              --------------------
                     4*4 - i*i
     
            = (40-1)+i(14)
               -----------
                   16+1
     
            = 39+14i
               ------
                 17
     
            = (39/17) + (14/17) i
    -R.Mangalesh
    Last edited by CaptainBlack; January 24th 2007 at 04:53 AM. Reason: to tidy up formatting
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