1. ## Pre-Algebra word problem

I am unsure of how to solve this problem and what 'e' would be:

A pizza with chesse and tomato toppings costs $8.00. It costs$1 for each extra topping.

a) Write a relation for the cost of a pizza with 'e' extra toppings.

I think that the equation would look like this:

P(pizza) = 8 + e

Would this be correct?

Thanks

2. Originally Posted by stouffie
I am unsure of how to solve this problem and what 'e' would be:

A pizza with chesse and tomato toppings costs $8.00. It costs$1 for each extra topping.

a) Write a relation for the cost of a pizza with 'e' extra toppings.

I think that the equation would look like this:

P(pizza) = 8 + e

Would this be correct?

Thanks
Indeed that is correct, just like if it were 3$per topping, the equation would be$\displaystyle P(pizza) = 8 +3e$. 3. let P = Price = (unit price) x (# of units), x = number of units,$1 = extra charge for each additional toppings

P = ($(8 + x))(x) P =$(8x + x^2) - - - answer,

for 1 unit only,

P = $(8 + 1)(1) =$9

ok

4. Originally Posted by pacman
let P = Price = (unit price) x (# of units),

x = number of units,

$1 = extra charge for each additional toppings P = ($(8 + x))(x)

P = $(8x + x^2) - - - answer, for 1 unit only, P =$(8 + 1)(1) = $9 ok Does that work for more than 1 topping though? 2 toppings would be$8 + 2$for the two toppings, with your equation$\displaystyle P = (8+2)(2)\displaystyle P = 20\$

5. It's all good. I just remembered that in the back of the text book are all the answers :P