Pre-Algebra word problem
I am unsure of how to solve this problem and what 'e' would be:
A pizza with chesse and tomato toppings costs $8.00. It costs $1 for each extra topping.
a) Write a relation for the cost of a pizza with 'e' extra toppings.
I think that the equation would look like this:
P(pizza) = 8 + e
Would this be correct?
Indeed that is correct, just like if it were 3$ per topping, the equation would be
Originally Posted by stouffie
let P = Price = (unit price) x (# of units),
x = number of units,
$1 = extra charge for each additional toppings
P = ($(8 + x))(x)
P = $(8x + x^2) - - - answer,
for 1 unit only,
P = $(8 + 1)(1) = $9
Does that work for more than 1 topping though?
Originally Posted by pacman
2 toppings would be $8 + 2$ for the two toppings, with your equation
It's all good. I just remembered that in the back of the text book are all the answers :P
The answer is e+8
to Kasper, thanks. i mixed the number of units with the number of toppings. it is a mistake indeed . . .