# Thread: Am I graphing this equation correctly?

1. ## Am I graphing this equation correctly?

Hello everyone!
I'm not sure if I'm doing this right. My instructions were to "Graph the given equations:"

$\displaystyle \frac{y}{3}-\frac{x}{6} = -2$

I'm using these numbers for x.
-2, -1, 0, 1, 2

This is what I've been doing:

(1) $\displaystyle \frac{y}{3}-\frac{-2}{6} = -2$

(2)Use LCD to get rid of fraction? *
I used: $\displaystyle \frac{3}{1}$ on both sides. then I got:
$\displaystyle y - \frac{-2}{2} = -6$

(3)$\displaystyle y - (-1) = -6$ *

(4)Then I added -1 to both sides.
$\displaystyle y = -7$

So that means my first point would be:
$\displaystyle (-2,-7)$

Then when I try to do it when $\displaystyle x = -1$
I get $\displaystyle y = -2$

With x = -1, I think I mess up on step 4.
$\displaystyle y - \frac{-1}{2} = - 6$

I subtract both sides with $\displaystyle \frac{-1}{2}$
And I keep getting $\displaystyle y = -2$

2. Originally Posted by Somatic
Hello everyone!
I'm not sure if I'm doing this right. My instructions were to "Graph the given equations:"

$\displaystyle \frac{y}{3}-\frac{x}{6} = -2$

I'm using these numbers for x.
-2, -1, 0, 1, 2

This is what I've been doing:

(1) $\displaystyle \frac{y}{3}-\frac{-2}{6} = -2$

(2)Use LCD to get rid of fraction? *
I used: $\displaystyle \frac{3}{1}$ on both sides. then I got:
$\displaystyle y - \frac{-2}{2} = -6$

(3)$\displaystyle y - (-1) = -6$ *

(4)Then I added -1 to both sides.
$\displaystyle y = -7$

So that means my first point would be:
$\displaystyle (-2,-7)$

Then when I try to do it when $\displaystyle x = -1$
I get $\displaystyle y = -2$

With x = -1, I think I mess up on step 4.
$\displaystyle y - \frac{-1}{2} = - 6$

I subtract both sides with $\displaystyle \frac{-1}{2}$
And I keep getting $\displaystyle y = -2$

Convert the equation into the form $\displaystyle y=mx+c$
$\displaystyle \frac{y}{3}-\frac{x}{6} = -2$
$\displaystyle \frac{y}{3} = -2 + \frac{x}{6}$
$\displaystyle y = \frac{x}{2} - 6 = \frac{x-12}{2}$
Now is should be easier to see that $\displaystyle f(-1)$ is $\displaystyle -\frac{13}{2}$ and $\displaystyle f(-2) = -7$