1 + 3 + 5 +.... (2n-1) = an^2 + bn + c, for some real constant a,b,c.Find the values of a,b and c
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Originally Posted by anshulbshah 1 + 3 + 5 +.... (2n-1) = an^2 + bn + c, for some real constant a,b,c.Find the values of a,b and c HI The first term is 1 and the last term is (2n-1) so $\displaystyle S_n=\frac{n}{2}(a+l)$ $\displaystyle =\frac{n}{2}(1+()2n-1)$ $\displaystyle =n^2$ So by comparing , a=1 , b and c are both 0 .
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