# Basic Algebra Word Problems (I got a few)

• Jan 23rd 2007, 12:19 PM
NemesysEvolved
Basic Algebra Word Problems (I got a few)
1. One-sixth of the sum of a certain number plus ten is equal to one-quarter of the number. What is it?

2. Find a number such that if it is multiplied by seven and eight is then added to the result, the new sum will be equal to eight times the original number.

thanks for ur help guys im doing this because I want to learn how to do it.
• Jan 23rd 2007, 12:28 PM
topsquark
Quote:

Originally Posted by NemesysEvolved
1. One-sixth of the sum of a certain number plus ten is equal to one-quarter of the number. What is it?

Call the number x. Then $\frac{x+10}{6} = \frac{x}{4}$

$\frac{x+10}{6} = \frac{x}{4}$ <-- Multiply both sides by 12.

$2(x + 10) = 3x$

$2x + 20 = 3x$

$20 = x$

So x = 20.

-Dan
• Jan 23rd 2007, 12:29 PM
topsquark
Quote:

Originally Posted by NemesysEvolved
2. Find a number such that if it is multiplied by seven and eight is then added to the result, the new sum will be equal to eight times the original number.

Call the number x. Then
$7x + 8 = 8x$

$x = 8$

-Dan
• Jan 24th 2007, 01:25 AM
mangaleswaranr
Quote:

Originally Posted by NemesysEvolved
1. One-sixth of the sum of a certain number plus ten is equal to one-quarter of the number. What is it?

2. Find a number such that if it is multiplied by seven and eight is then added to the result, the new sum will be equal to eight times the original number.

thanks for ur help guys im doing this because I want to learn how to do it.

1. 1/6(x+10)=x/4

multiply by 24

4(x+10)=6x
4x+40=6x
remove 4x from both sides
40=2x
both sides divided by 2