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Thread: Log Problem

  1. September 29th 2009, 07:31 PM #1
    VkL
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    Log Problem

    Simplify 3ln(e^A) + 4lnB^e

    How do i start?
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  2. September 29th 2009, 07:52 PM #2
    pickslides
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    Use the following

    c\times \log_ab = \log_ab^c

    and

    \log_ab+\log_ac = \log_a(b\times c)
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  3. September 29th 2009, 08:33 PM #3
    VkL
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    So i raise the the 3 to the top? ..ln(e^a)^3 + lnB^e^4 ???
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  4. September 29th 2009, 09:16 PM #4
    pickslides
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    thats a good start
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