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Math Help - Linear problem

  1. #1
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    Linear problem

    How would I express in standard form: contains point (-1,4) and is parallel to x-5y=5?
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  2. #2
    Master Of Puppets
    pickslides's Avatar
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    I think you are looking for the line that is parallel to x-5y=5 that contains the point (-1,4) ?

    Haivng a play with this guy gives.

    x-5y=5

    -5y=5-x

    y=\frac{5}{-5}-\frac{x}{-5}

    has the gradient m= \frac{1}{5}

    So the line you need to find is y = \frac{1}{5}x+c with (-1,4)

    4 = \frac{1}{5}\times -1+c

    Now solve for c
    Last edited by pickslides; September 30th 2009 at 03:15 PM.
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  3. #3
    Senior Member pacman's Avatar
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    that contains the point ,we have

    x - 5 = 5y, divide BS by 5,

    y = (1/5)x - (5/5),

    y = (1/5)x - 1, - - - - (1)

    compare it with intercept-slope form, y = mx + b

    m = 1/5, if another line parallel to it passing through (-1,4), we have

    4 = (1/5)(-1) + c, solving for c

    4 = -1/5 + c,

    4 + 1/5 = c,

    (20 + 1)/5 = c,

    21/5 = c

    thus the line's equation is,

    y = (1/5)x + 21/5 - - - - (2)

    see the plot below . . . . JUST double CLICK the picture for a BETTER VIEW.
    Attached Thumbnails Attached Thumbnails Linear problem-aqwer.gif  
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