Thread: Linear problem

How would I express in standard form: contains point (-1,4) and is parallel to x-5y=5?

I think you are looking for the line that is parallel to that contains the point ?

Haivng a play with this guy gives.







has the gradient

So the line you need to find is with



Now solve for c

that contains the point ,we have

x - 5 = 5y, divide BS by 5,

y = (1/5)x - (5/5),

y = (1/5)x - 1, - - - - (1)

compare it with intercept-slope form, y = mx + b

m = 1/5, if another line parallel to it passing through (-1,4), we have

4 = (1/5)(-1) + c, solving for c

4 = -1/5 + c,

4 + 1/5 = c,

(20 + 1)/5 = c,

21/5 = c

thus the line's equation is,

y = (1/5)x + 21/5 - - - - (2)

see the plot below . . . . JUST double CLICK the picture for a BETTER VIEW.