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Math Help - help once more

  1. #1
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    Exclamation help once more

    simplify: 3a to the 3rd power times b to the 2nd power + 5a to the second power times b to the second power minus 14ab to the second power minus 3a to the third power times b to the second power
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  2. #2
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    Quote Originally Posted by RashanHoliday View Post
    simplify: 3a to the 3rd power times b to the 2nd power + 5a to the second power times b to the second power minus 14ab to the second power minus 3a to the third power times b to the second power
    Are you sure this is right? The first and last terms are identical.

    (3a)^3b^2 + (5a)^2b^2 - (14ab)^2 - (3a)^3b^2 <-- Cancelling the first and last terms.

    (5ab)^2 - (14ab)^2

    25a^2b^2 - 196a^2b^2

    (25 - 196)a^2b^2

    -171a^2b^2

    -Dan
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