help on this one Solve: 4 – 6(x + 2)> or = to 5x + 36
hey,
how did you get x is more than or equal to 4? Shouldn't it be x is less than or equal to 4? Here's my reasoning.
1. Distribute the x
2.Add 12 to both sides
3. subtract 4 from both sides
4.subtract 5x from both sides
5. divide by negative 11 (you flip the sign when you divide by a negative)
6. You wind up getting x is less than or equal to negative 4.
start with:
$\displaystyle 4-6(x+2) \ge 5x+36$
I presume you mean distribute the 61. Distribute the x
$\displaystyle 4-6x-12 \ge 5x+36$
$\displaystyle 4-6x \ge 5x+48$2.Add 12 to both sides
$\displaystyle -6x \ge 5x+44$3. subtract 4 from both sides
$\displaystyle -11x \ge 44$4.subtract 5x from both sides
$\displaystyle x \le -4$5. divide by negative 11 (you flip the sign when you divide by a negative)
Yes, but that is what earboth has:6. You wind up getting x is less than or equal to negative 4.
$\displaystyle x \le -4$ and $\displaystyle -4 \ge x$ are the same thing.
RonL
Hello,
sorry for this late reply:
1. if you read my answer from right to left you'll get exactly your answer
2. I collected the x at the RHS to avoid the division by a negative number. As you have pointed out you have to change the $\displaystyle \geq$-sign into a $\displaystyle \leq$-sign, which I don't have to do.
EB