Hello
I have equation:Equation has 2 solutions. p and q are integer and positive. How many different p and q exsist if both solutions are less then 5 (x1,x2<5).Code:x^2 - px + q = 0
Sorry for my English. Please help. Cheers.
I do not understand this (x1,x2<5).
Could you explain what that means in this situation?
Since p & q are integers, x must be greater than zero, and an integer.
That's eight solutions.Code:x p q 1 1 0 1 2 1 1 3 2 1 4 3 2 2 0 2 3 2 2 4 4 3 4 3
If you removed x=1, p=1, q=0 and x=2, p=2, q=0, you would still have 6 solutions.
Could you explain the restrictions so that only 2 work?
x1 and x2 are roots
Root (mathematics) - Wikipedia, the free encyclopedia
Sorry for my English
Condition 1:
Since roots are real and distinct:
................................(1)
Condition 2:
Since both roots are less than ,the sum of the roots will be less than .
Condition 3:
Let
From conditions 1,2 and 3 we can see that and ,where p and q are integers
I hope this helps.
Thx
But I don't know how many p&q satisfy the condition x^2 - px + q = 0 ?
For exaple in this reason result is 16 (I have written program in c++ and check a lot of p & q, if condition was satisfied r++ and r was a resault).
How can I get that?