How can I solve for n for something of this form? (1.14)^(1/n) - 1 = 0.13/n I managed to arrive at this: n[(1.14)^(1/n) -1] = 0.13 But I don't know where to go from there.
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Originally Posted by Volcanicrain How can I solve for n for something of this form? (1.14)^(1/n) - 1 = 0.13/n I managed to arrive at this: n[(1.14)^(1/n) -1] = 0.13 But I don't know where to go from there. I don't know a way to solve this equation algebraically. I would use Newton's method to get an approximate value for n: Solve for n. I got
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