I am doing lots of word problems and so far I was doing pretty good. For some reason I can't figure this one out. I am hoping someone is able to help me.
In a two-digit number , the ten's digit is 3 more than the one's digit. If the digits are reversed, the difference between the two numbers is 27. Find the number.
ten's digit= x+3 one's digit = x
10(x+3) + x
reversed would be 10x + x+3 -27 = 10(x+3)+x ??? I don't get it.