Changing the subject involving division (2)

**Meggomumsie** · September 29th 2009, 12:12 AM

Hi, I thought I could do this last question in my exercise book but I have gone wrong somewhere. Could someone show me where please?

$f=\frac{uv}{u+v}$

$f(u+v)=uv$

$fu+fv=uv$

$fv=uv-fu$

$\frac{fv}{v-f}=u-u$

**bram kierkels** · September 29th 2009, 12:59 AM

Originally Posted by Meggomumsie

Hi, I thought I could do this last question in my exercise book but I have gone wrong somewhere. Could someone show me where please?

$f=\frac{uv}{u+v}$

$f(u+v)=uv$

$fu+fv=uv$

$fv=uv-fu$

$\frac{fv}{v-f}=u-u$

In the 4th step you make a mistake;

$fv=uv-fu$

$fv=u(v-f)$

$\frac{fv}{v-f}=u$

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