Can someone please put me on the right track to solving these problems? If you can provide an example for at least one of each, I would greatly appreciate it. Thanks so much. Please see attachment. ,:( :confused:
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Can someone please put me on the right track to solving these problems? If you can provide an example for at least one of each, I would greatly appreciate it. Thanks so much. Please see attachment. ,:( :confused:
Why is this a problem?Quote:
Question 1:
Use the arithmetic sequence of numbers 2, 4, 6, 8, 10… to find the following:
What is d, the difference between any 2 terms?
the differences can be written:
(4-2)=2, (6-4)=2, (8-6)=2, (10-8)=2.
the first term is 2, the second term is 2+2=4, the third term is 2+2+2=6, the n-th term is 2+2+....+2 (with n terms) which is equal to 2n.Quote:
Question 2:
Using the formula for the nth term of an arithmetic sequence, what is 101st term?
Therefore the 101-st tem is 1x101=202.
You need to know the formula for the sum of an arithmetic progression.Quote:
Using the formula for the sum of an arithmetic sequence, what is the sum of the first 20 terms?
S(n)=(1/2)n(2a+(n-1)d)
here first term a=2, common difference d=2 and n=20, so:
S(20)=(1/2)x20x(4+19x2)=420
RonL
Hello, fw_mathis!
Are you really having trouble with these problems?
Do you know what "difference between any two terms" means?
. . And you're expected know the necessary formulas.
So where exactly is your difficulty?
Quote:
Using the arithmetic sequence of numbers:to find the following:
What is, the difference between any two consecutive terms?
The difference between 2 and 4 is . . . um . . . 2 ?
The difference between 4 and 6 is . . . er . . . 2 ?
Quote:
Using the formula for theterm of an arithmetic sequence, what is the
term?
The formula for theterm is: .
. . where= first term,
= common difference,
= number of terms.
We have: .
Therefore: .
Quote:
Using the formula for the sum of an arithmetic sequence,
. . what is the sum of the firstterms?
Formula: .
We have: .
Therefore: .
I'll let someone else teach you about Geometric Sequences . . .