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Math Help - subtracting a fraction containing a variable by another fraction without variables.

  1. #1
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    subtracting a fraction containing a variable by another fraction without variables.

    I know this is easy, but i was wondering what the method is for doing this..

    thank you!
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  2. #2
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    = \ \frac{6(x+5)-8(x+3)}{6(x+3)} \times \frac{1}{(x-3)}
    =\\ \frac{6x+30-8x-24}{6(x+3)(x-3)}
     =\\ \frac{-2x+6}{6(x+3)(x-3)}
    = \\ \frac{-2(x-3)}{6(x+3)(x-3)}
    =\\ \frac{-1}{3(x+3)}
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  3. #3
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    Thank you, but i meant from the middle part of the eq. where it has ((x+5)/(x+3))-(8/6).
    Im not sure what method they used to subtract the 2. ~Evan
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