the question is:

the parabola with equation $\displaystyle y = 2x^2 + 4x - 8$ intersects the line $\displaystyle y + kx + 4k = 0$ where k is a constant.

show that any points of intersection have x coordinates that satisfy $\displaystyle 2x^2 + (k + 4)x + 4(k - 2) = 0$

how would you show this? thanks