What is my first move please?
$\displaystyle y=\frac{5+x}{1-x}$
Hello MeggomumsieGet rid of fractions - always a good move in handling any equation. So, multiply both sides by $\displaystyle (1-x)$:
$\displaystyle y(1-x) = 5+x$
Then:
- Remove brackets on the LHS
- Collect terms in $\displaystyle x$ on one side only; everything else on the other side
- Take out a common factor of $\displaystyle x$ (by writing $\displaystyle x$ outside a bracket with the other bits inside)
Divide both sides by the resulting bracket to make $\displaystyle x$ the subject.
Can you complete it now?
Grandad
Thank you for your answer. I would still be pondering without your prompts as I have not been taught to factorise in the middle of changing the subject of a formula. So here is my attempt.
$\displaystyle y=\frac{5+x}{1-x}$
y(1 - x) = 5 + x
y - xy = 5 + x
y -5 = x + xy
y - 5 = x(1 + y)
$\displaystyle \frac{y-5}{y+1}=x$
It's great to be learning, thank you all ~ Marilyn