Not sure where to start with this one
$\displaystyle a=2\sqrt{b^2-2}$ (Make b the subject of the formula)
How do I begin please? I can't see how to square everything at all this time, not even incorrectly.
Not sure where to start with this one
$\displaystyle a=2\sqrt{b^2-2}$ (Make b the subject of the formula)
How do I begin please? I can't see how to square everything at all this time, not even incorrectly.
$\displaystyle a = 2\sqrt{b^2 - 2}$
$\displaystyle a^2 = (2\sqrt{b^2 - 2})^2$
$\displaystyle a^2 = 4(b^2 - 2)$
$\displaystyle \frac{a^2}{4} = b^2 - 2$
$\displaystyle \frac{a^2}{4} + 2 = b^2$
$\displaystyle \frac{a^2 + 8}{4} = b^2$
$\displaystyle \sqrt{\frac{a^2 + 8}{4}} = b$
$\displaystyle b = \frac{\sqrt{a^2 + 8}}{2}$.