5 = 2x + 3y/3x +5y

how do i isolate for x/y ?

Thanks

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- Sep 26th 2009, 03:50 PMrishalgebra problem
5 = 2x + 3y/3x +5y

how do i isolate for x/y ?

Thanks - Sep 26th 2009, 03:55 PMFreaky-Person
I'm seeing $\displaystyle \frac{3y}{3x}$ and wondering if maybe something was mistyped. It's not that it's wrong, it's just that the 3 is obviously going to cancel out, so why is it in there...?

Also, what do you mean by isolate? Do you mean change it into a y= form? - Sep 26th 2009, 04:00 PMrish
Oh sorry,

I mean to say 5x + 6y in the denominator

I just need to to solve for x an y

sorry about that - Sep 26th 2009, 04:05 PMskeeter
I'm assuming ...

$\displaystyle 5 = \frac{2x+3y}{3x+5y}$

$\displaystyle 15x + 25y = 2x + 3y$

since $\displaystyle y \ne 0$ , divide every term by $\displaystyle y$ ...

$\displaystyle 15\cdot \frac{x}{y} + 25 = 2 \cdot \frac{x}{y} + 3$

$\displaystyle 13\cdot \frac{x}{y} = -22$

$\displaystyle \frac{x}{y} = -\frac{22}{13}$