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Math Help - Bleh need some help :(

  1. #1
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    Bleh need some help :(

    1\over(x+h)^2 - 1\over x^2

    Not very good at that LaTeX sort of stuff but here is what im stuck with and have to simplify it.

    Its also all over h but no idea how to get that there :/

    Anyways any suggestions?
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  2. #2
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    Quote Originally Posted by Djaevel View Post
    1\over(x+h)^2 - 1\over x^2

    Not very good at that LaTeX sort of stuff but here is what im stuck with and have to simplify it.

    Its also all over h but no idea how to get that there :/

    Anyways any suggestions?
    get a common denominator and combine the two fractions.
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  3. #3
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    Quote Originally Posted by Djaevel View Post
    1\over(x+h)^2 - 1\over x^2

    Not very good at that LaTeX sort of stuff but here is what im stuck with and have to simplify it.

    Its also all over h but no idea how to get that there :/

    Anyways any suggestions?
    If it's all over h I would multiply that by \frac{1}{h}:

    \frac{1}{h}(\frac{1}{(x+h)^2} - \frac{1}{x^2})

    ----------------------------

    Ignoring that h for now:

    \frac{1}{x^2+2hx+h^2} - \frac{1}{x^2}

    Cross multiply:

    \frac{2x^2+2hx+h^2}{x^2(x^2+2hx+h^2)}

    I admit it's very messy though. What did you need to find?
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  4. #4
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    See i dont understand how you got the top part? I mean i did get the bottom somehow :/

    Everything on here is all from my university pre calculus math class, and i dont remember ANYTHING from math 12 so im having a pretty rough time.

    Like i dont remember most of the information from the units i've already done
    Last edited by mr fantastic; September 28th 2009 at 08:41 PM. Reason: Merged posts
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  5. #5
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    \frac{1}{h} \left[\frac{1}{(x+h)^2} - \frac{1}{x^2}\right]

    \frac{1}{h} \left[\frac{x^2}{x^2(x+h)^2} - \frac{(x+h)^2}{x^2(x+h)^2}\right]

    \frac{1}{h} \left[\frac{x^2 - (x^2 + 2xh + h^2)}{x^2(x+h)^2}\right]

    \frac{1}{h} \left[\frac{-2xh - h^2}{x^2(x+h)^2}\right]

    \frac{1}{h} \left[\frac{-h(2x + h)}{x^2(x+h)^2}\right]

    -\frac{2x + h}{x^2(x+h)^2}
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  6. #6
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    Thanks skeeter always a great help
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