Originally Posted by

**evankimia** Its been a while since i took a math course, and i completely forgot how to solve for X in this equation.... y=4x-1/2x+3. I looked it up and found this from yahoo answers...

1. (x) = (4x-1) / (2x+3)

2 y = (4x-1) / (2x+3)

3. y(2x+3) = 4x-1

4. 2xy+3y = 4x-1

5. 2xy - 4x = -3y-1

6. 2x(y-2) = -3y-1

7. x =(-3y-1)/[2(x-2)]

8. f^-1(y) = (-3y-1)/[2(x-2)]

...my question is in step 5 above what did he do to get 2xy-4x from 2xy-3y, and also the procedure from steps 5 to 6 and 6 to 7.

Thanks.