Solve

-16x^(-2)+2x=0

and

-9x^2+1=0

but how do you do it?

million thanks!

2. Hello, BabyMilo!

Solve: . $-16x^{-2}+2x\:=\:0$

Answer: $2\text{ or }0$ . . . . not true

but how do you do it?

We have: . $2x - 16x^{-2} \:=\:0$

Multiply by $x^2\!:\;\;2x^3 - 16 \:=\:0$

Factor: . $2(x^3-8)\:=\:0 \quad\Rightarrow\quad x^3 \:=\:8$

Therefore: . $x \:=\:2$

3. thanks!

4. Originally Posted by BabyMilo

-9x^2+1=0

but how do you do it?

million thanks!
-9x^2 + 1 = 0
-9x^2 = -1
x^2 = 1/9
x = 1/3