1. ## help please with this problem

could anyone show me how to work this out please...
a wage bill for 16 craftsmen and 5 apprentices was £740. a second wage bill for 9 craftsmen and 30 apprentices was the same amount. by using simultaneous equations find the weekly wage of a>the craftsperson and b>the apprentice
many thanx
jim

2. Hello, jim49990!

A wage bill for 16 craftsmen and 5 apprentices was \$740.
A second wage bill for 9 craftsmen and 30 apprentices was the same amount.
By using simultaneous equations find the weekly wage of (a) a craftsman and (b) an apprentice.

Let $C$ be the wage of a craftsman.
Let $A$ be the wage of an apprentice.

We are told that: . $\begin{array}{cc}16C + 5A & =\;740 \\ 9C + 30A & =\;740\end{array}$

Now solve the system by your favorite method: .elimination, substitution,
. . Cramer's Rule, augmented matrix, inverse matrix, etc.

3. Originally Posted by jim49990
could anyone show me how to work this out please...
a wage bill for 16 craftsmen and 5 apprentices was &#163;740. a second wage bill for 9 craftsmen and 30 apprentices was the same amount. by using simultaneous equations find the weekly wage of a>the craftsperson and b>the apprentice
many thanx
jim
wages of craftsman is x &#163;
wages of apprentices is y&#163;

the simultaneous equations are
16x + 5y =740 ----(1)
9x + 30y = 740 ---(2)

(1) x 6 ---> 96x+30y=4440
(2) x 1----> 9x+30y= 740

sub 87x = 3700

therefore x = 42.52 sub in (1)
we get y = 11.91 (apprx)

- R.Mangaleshwaran