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Math Help - How do I solve and get the right answer??

  1. #1
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    How do I solve and get the right answer??

    PS. can anyone write this using Latex too??
    Attached Thumbnails Attached Thumbnails How do I solve and get the right answer??-problem-5.1-77.jpg  
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  2. #2
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    10 b^3 is correct.
    When you changed ^(-1/3) to ^(1/3), you should bring up
    the denominator to the numerator; 1 / n^(-1/3) = n^(1/3).
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  3. #3
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    Question

    would it be possible that someone shows me the procedure to solve it. I still have the same result...!
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  4. #4
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    As the denominator is to the power -1/3 you need to root it as you have but as it is a negative power it moves up.

    (5a^3 b^2)(2a^-3 b)=10b^3

    You were very close.
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  5. #5
    Junior Member Freaky-Person's Avatar
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    behold, my Latex skills! For I'm useless elsewhere!

    \frac{(25a^6 b^4)^\frac{1}{2}}{(8a^{-9} b^3)^{-\frac{1}{3}}} = (25a^6 b^4)^\frac{1}{2}(8a^{-9} b^3)^{\frac{1}{3}} = (5a^3 b^2)(2a^{-3} b) = 10b^3


    ain't it pretty? :3
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  6. #6
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    I must get around to learning latex.

    A communication essential on this forum I think.
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  7. #7
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    Uppss!
    Last edited by Alienis Back; October 2nd 2009 at 01:08 PM.
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