# Math Help - How do I solve and get the right answer??

1. ## How do I solve and get the right answer??

PS. can anyone write this using Latex too??

2. 10 b^3 is correct.
When you changed ^(-1/3) to ^(1/3), you should bring up
the denominator to the numerator; 1 / n^(-1/3) = n^(1/3).

3. would it be possible that someone shows me the procedure to solve it. I still have the same result...!

4. As the denominator is to the power -1/3 you need to root it as you have but as it is a negative power it moves up.

(5a^3 b^2)(2a^-3 b)=10b^3

You were very close.

5. behold, my Latex skills! For I'm useless elsewhere!

$\frac{(25a^6 b^4)^\frac{1}{2}}{(8a^{-9} b^3)^{-\frac{1}{3}}} = (25a^6 b^4)^\frac{1}{2}(8a^{-9} b^3)^{\frac{1}{3}} = (5a^3 b^2)(2a^{-3} b) = 10b^3$

ain't it pretty? :3

6. I must get around to learning latex.

A communication essential on this forum I think.

7. Uppss!