PS. can anyone write this using Latex too??
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10 b^3 is correct.
When you changed ^(-1/3) to ^(1/3), you should bring up
the denominator to the numerator; 1 / n^(-1/3) = n^(1/3).
would it be possible that someone shows me the procedure to solve it. I still have the same result...!
As the denominator is to the power -1/3 you need to root it as you have but as it is a negative power it moves up.
(5a^3 b^2)(2a^-3 b)=10b^3
You were very close.
behold, my Latex skills! For I'm useless elsewhere!
ain't it pretty? :3
I must get around to learning latex.
A communication essential on this forum I think.
Last edited by Alienis Back; Oct 2nd 2009 at 12:08 PM.
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