Thread: Need Help with Equation Word Problem

1. Need Help with Equation Word Problem

Hello all. Well, I received such wonderful help the first time I used this forum so I am returning with yet another equation word problem that has me stumped. When I check my work, the answer I keep coming up with is not making any sense and does not fit. Here is the problem followed by the answer I keep getting, hopefully someone will see what I am doing wrong and steer me in the right direction

Use an equation to solve: Patricia’s bill for one year of college is $24,500. The tuition charge costs$4,000 more than the room and board costs. This bill also includes $500 for fees and other charges. How much is the yearly tuition charge? 24,500 - 4,000 =20,500/2 =10,250 + 500 =10,750 (my answer) As you can see, this makes no sense because if you take my answer, add the room and board, the other charges and the 4,000 which gives you 1,000 too much 10,750 + 10,250 + 500 + 4000 = 25,500 2. Originally Posted by dclary Hello all. Well, I received such wonderful help the first time I used this forum so I am returning with yet another equation word problem that has me stumped. When I check my work, the answer I keep coming up with is not making any sense and does not fit. Here is the problem followed by the answer I keep getting, hopefully someone will see what I am doing wrong and steer me in the right direction Use an equation to solve: Patricia’s bill for one year of college is$24,500. The tuition
charge costs $4,000 more than the room and board costs. This bill also includes$500
for fees and other charges. How much is the yearly tuition charge?

24,500 - 4,000
=20,500/2
=10,250 + 500

As you can see, this makes no sense because if you take my answer, add the room and board, the other charges and the 4,000 which gives you 1,000 too much

10,750 + 10,250 + 500 + 4000 = 25,500
Hi dclary,

Let's define what we know and what we don't know.

Let r = room and board costs

Let r + 4000 = tuition costs (tuition is $4000 more than room and board) Let 500 = other costs (fees and charges) Let 24500 = total costs Now, let's add all this up to the total costs: r + r + 4000 + 500 = 24500 How's that look? Solve for r to get room and board costs. Then add 4000 to get your tuition costs 3. RE: Need Help with Equation Word Problem Thank you so much. If I am correctly solving for "r" the answer would be 10,000 is that correct? Thank you again for your help, I really appreciate it. 4. Originally Posted by dclary Thank you so much. If I am correctly solving for "r" the answer would be 10,000 is that correct? Thank you again for your help, I really appreciate it. Yes, you are correct. And the tuition cost will be$4000 more than that.

5. Originally Posted by dclary
Hello all. Well, I received such wonderful help the first time I used this forum so I am returning with yet another equation word problem that has me stumped. When I check my work, the answer I keep coming up with is not making any sense and does not fit. Here is the problem followed by the answer I keep getting, hopefully someone will see what I am doing wrong and steer me in the right direction

Use an equation to solve: Patricia’s bill for one year of college is $24,500. The tuition charge costs$4,000 more than the room and board costs. This bill also includes $500 for fees and other charges. How much is the yearly tuition charge? 24,500 - 4,000 =20,500/2 =10,250 + 500 =10,750 (my answer) As you can see, this makes no sense because if you take my answer, add the room and board, the other charges and the 4,000 which gives you 1,000 too much 10,750 + 10,250 + 500 + 4000 = 25,500 let x be the room and board costs since tuition is 4000 more than room and board then the eq becomes $x+x+4000+500=24500$ $2x=20000$ $x=10000$ tuition=x+4000=$14000