Write in exponential form: (there is a exponent like 3 before the square root) a. ^3 square root p^4q (there is a exponent like 3 before the square root) b. ^3 square root x^6y^-4
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Originally Posted by gracy Write in exponential form: (there is a exponent like 3 before the square root) a. ^3 square root p^4q (there is a exponent like 3 before the square root) b. ^3 square root x^6y^-4 a.) I'm assuming this is what you're asking for: (p^4*q)^(2/3) Or, equivalently: ((p^q)^4)^2/3 b.) (x^6*y^(-4))^(3/2) = [(x^6)/(y^4)]^(3/2) = (x^9)/(y^6)
I am really confused. the question is (a) cube root(p^4q ) (b) cube root (x^6y^-4)
Last edited by gracy; Jan 21st 2007 at 11:10 PM.
Originally Posted by gracy I am really confused. the question is (a) cube root(p^4q ) (b) cube root (x^6y^-4) a) cubrt[(p^4)(q)] = [(p^4)(q)]^(1/3) = [p^(4 *1/3)]*[q^(1/3)] = [p^(4/3)]*[q^(1/3)] -------------answer. ---------------------------------------------------- cubrt[(x^6)(y^4)] = [(x^6)(y^4)]^(1/3) = [x^(6 *1/3)][y^(4 *1/3)] = [x^2][y^(4/3)] ----------------answer.
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