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**coobe** $\displaystyle \frac {-4x^2} {2-x} < 2-4x$

im not sure about my result.

as far i can see i must look at 2 cases. 1st: x > 2 and 2nd x < 2

the first would give me the solution: $\displaystyle -\frac {2} {3} < x$

which leads me to the first set of solutions: x > 2

am i right here ?

the 2nd case would give me the same just with flipped inequality sign

so the overall solution i got is: all real numbers except the intervall $\displaystyle [-\frac {2}{3}, 2]$

somehow all my math programs give me the solution: -2/3 < x < 2

i cant see why that is :(