When P(z) is divided by (z^2) - 3z + z the remainder is 4z-7. Find the remainder when P(z) is divided by: a) (z-1) b) (z-2)
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Originally Posted by karldiesen When P(z) is divided by (z^2) - 3z + z the remainder is 4z-7. Find the remainder when P(z) is divided by: a) (z-1) b) (z-2) Please review this posting. Is that really what the question says?
no, it was just a weird way of writing a quadratic equation!
Originally Posted by karldiesen When P(z) is divided by (z^2) - 3z + z the remainder is 4z-7. Find the remainder when P(z) is divided by: a) (z-1) b) (z-2) Originally Posted by Plato Please review this posting. Is that really what the question says? Originally Posted by karldiesen no, it was just a weird way of writing a quadratic equation! I am will to wager that is incorrect. I bet that it is . It is the only way to make sense of the question. Theorem: If the polynomial is divided by then the remainder is . In this problem we have . Now use the theorem,
Originally Posted by Plato I am will to wager that is incorrect. I bet that it is . It is the only way to make sense of the question. Theorem: If the polynomial is divided by then the remainder is . In this problem we have . Now use the theorem, You are absolutely correct, that is what I was trying to write. I just didn't know how to write the exponents! But I am still stuck! I just can't see how I can get a solution...
What are
They are equal to the remainder!
Originally Posted by karldiesen They are equal to the remainder! READ Theorem: If the polynomial is divided by then the remainder is .
Originally Posted by Plato READ Theorem: If the polynomial is divided by then the remainder is . Ah, now it is finally clear to me! My head was just making the problem look impossible! Thanks alot!
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