can someone show me how to factorise $\displaystyle x^2 - 3$ thanks
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$\displaystyle x^2-3=(x-\sqrt{3})(x+\sqrt{3})$
thankyou, could you show me how it works like that please? i mean, how you figured it out
Originally Posted by mark can someone show me how to factorise $\displaystyle x^2 - 3$ thanks Hi $\displaystyle x^2-(\sqrt{3})^2=(x+\sqrt{3})(x-\sqrt{3}) $
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