
"Mystery bag" problem
Hi again MHF,
I'm a bit confused so any help you can provide is greatly appreciated. Thanks a lot. :)
"Describe how the jester must place the mystery bags and lead weights so that the equation will be a representation of the situation.
Then find the weight of the mystery bag."
a. 5M + 24 = 51 + 2M
b. 43M + 37 = 56M + 24
c. 12M + 15 = 5M + 62

does M equal the mystery weight of the bag?

From what I understand, yes.

From what I understand, they want you to make M the subject of the equation, or, in other words, find the value of M.
To do this, we need to understand the process of undoing/manipulating equations.
The opposite of Addition is Subtraction
The opposite of Multiplication is Division
Hence, to make M the subject in these equations we need to undo some of the operations and shift a few things around.
a. 5M + 24 = 51 + 2M  The aim is to get the M's onto one side, whilst keeping both sides equal (like keeping weights in balance on a scale).
Let's push M onto the left side, as it's mathematical convention for the subject to appear on the left.
a. 5M + 24 = 51 + 2M
1. Get M onto the left side.
3M + 24 = 51 (We substracted (opposite of addition) 2M from both sides (keeping the equation balanced).)
2. Get M by itself.
3M = 27 (We need to undo the addition of 24 (opposite is substraction) before we can deal with the 3 in front of the M).
 M = 27/3 = 9 (We undid the multiplication on M by dividing both sides by 3 (opposite to the multiplication).
If you understand the process, can you complete the rest by yourself?

Yes, I do understand  and thanks for your assistance once again (Nod)