Results 1 to 3 of 3

Math Help - [SOLVED] Changing fractions to have their least common denominator equivalent

  1. #1
    VHIStudent7
    Guest

    Unhappy [SOLVED] Changing fractions to have their least common denominator equivalent

    Ok, I am having a really hard time understanding this. I thought I did but the answer key has a different answer than what I thought it was.

    Here's the problem:

    change 2m and m+n/m-n to fractions having their least common denominator.

    How do I solve this problem?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Apr 2005
    Posts
    1,631
    If I understand what you mean, you want to combine the two terms into one fraction.

    2m +(m+n)/(m-n)
    = [2m(m-n) +(m+n)] / (m-n)
    = [2m^2 -2mn +m +n] / (m-n)

    That is it.

    -------------
    Or, you meant:

    2m(m-n) / (m-n), and (m+n) / (m-n)
    Those are two fractions having a least common denominator.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Oct 2005
    Posts
    27
    change 2m and m+n/m-n to fractions having their least common denominator.


    SInce only one of the terms has a denom, that is the least common.

    Let's start with little numbers: 3 and 5/8 Since all whole numbers are understood to have a denom of 1, we must multiply the denom by 8 to have the same denom as the fraction. When we multiply the bottom by 8, we must be sure to multiply the top by 8 also in order to keep the value equal, so we have 3 = 24/8

    So in your problem, we have 2m /1 Multiply top and bottom by the other denom --> 2m(m-n) --> [2m^2 -2mn] / [m-n] is the 1st fraction. The other fraction remains the same.

    Hope this is helpful to you.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Common denominator
    Posted in the Algebra Forum
    Replies: 4
    Last Post: August 31st 2010, 02:27 AM
  2. Replies: 1
    Last Post: January 23rd 2010, 09:19 AM
  3. common denominator
    Posted in the Algebra Forum
    Replies: 10
    Last Post: November 8th 2009, 07:57 AM
  4. [SOLVED] rational polynomial common denominator
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: April 18th 2009, 01:53 PM
  5. [SOLVED] Fractions with surds in the denominator
    Posted in the Math Topics Forum
    Replies: 3
    Last Post: March 16th 2009, 10:11 PM

/mathhelpforum @mathhelpforum