Hai, everyone..once again, its me, Ah Chan. Sorry for I'm quite inactive this last few weeks because I got lot of problems banging my doors and so busy, rushing the assignment...anyways, thanks to everyone for my previous last questions. Erm, I got a proofing question here that had took me quite a long times yet I haven't fully understand the solution for it, mind to help me out...thanks a lot anyways
Prove for distance from a point to line formula;
First, show that the distance from O (0,0) to Ax+By+C=0 is lCl / (square root)[A^2 + B^2] by finding the area of the shaded triangle using two different altitudes and then equating the areas....(Hints: Draw a right-angle triangle with two points, [0,(-C/B)] and [(-C/A),0]
Then, now translate (h,k) and the line Ax+By+C=0 by the same amount so that (h,k) moves to (0,0)...
The answer should be d = lAh+Bk+Cl / (square root)[A^2+B^2]..but I just couldn't figured it out, please do help me..thanks