Could someone help me with this one? Use substitution to solve the system | y=2-x/2 | x[squared]+4y=8
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Originally Posted by gretchen Could someone help me with this one? Use substitution to solve the system | y=2-x/2 | x[squared]+4y=8 y = 2 - (x/2) x^2 + 4y = 8 We'll substitute y; x^2 + 4(2 - (x/2)) = 8 x^2 + 8 - 2x = 8 x^2 - 2x = 0 x*(x - 2) = 0 x = 0 V x = 2 CHECK: y = 2 - (x/2) x^2 + 4y = 8 ---------------- y = 2 - (0/2) y = 2 And y = 2 - (2/2) y = 1 0^2 + 4(2) = 8 ? Yes; 2^2 + 4(1) = 8 ? Yes.
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