Could someone help me with this one?

Use substitution to solve the system | y=2-x/2

| x[squared]+4y=8

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- Jan 20th 2007, 09:35 PMgretchenSubstitution
Could someone help me with this one?

Use substitution to solve the system | y=2-x/2

| x[squared]+4y=8 - Jan 20th 2007, 10:26 PMAfterShock
y = 2 - (x/2)

x^2 + 4y = 8

We'll substitute y;

x^2 + 4(2 - (x/2)) = 8

x^2 + 8 - 2x = 8

x^2 - 2x = 0

x*(x - 2) = 0

x = 0 V x = 2

CHECK:

y = 2 - (x/2)

x^2 + 4y = 8

----------------

y = 2 - (0/2)

y = 2

And y = 2 - (2/2)

y = 1

0^2 + 4(2) = 8 ?

Yes;

2^2 + 4(1) = 8 ?

Yes.