Originally Posted by

**EddieG** Could somone please look over this equation and check for errors.

$\displaystyle (X+3)/4-(X-4)/2=3/8$

$\displaystyle (2)(X+3)/4-(4)(X-4)/2=3/8$ Mr F says: You have the wrong denominators here. It should be $\displaystyle {\color{red}(2)(X+3)/{\color{blue}8} -(4)(X-4)/{\color{blue}8} = 3/8}$. The next line seems to have used the correct denominators.

$\displaystyle (2x+6-4x {\color{blue}-} 16)/8=3/8$ Mr F says: The first mistake (excluding mistakes in setting out - see above) is in blue. The blue minus should be a plus. This will affect all that follows.

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