1. ## can someone please answer these three questions

what is the slope of the line that passes through points (-2, -1) and (5, 6)

what is the slope of the line that passes through points (2, 4) and (-3, 4)

are the lines 2x + 5y = 1 and y = 5/2x + 4 parallel, perp, neither, or the same

2. Originally Posted by tyonna
what is the slope of the line that passes through points (-2, -1) and (5, 6)

what is the slope of the line that passes through points (2, 4) and (-3, 4)

for the first two ...

$\textcolor{red}{m = \frac{y_2-y_1}{x_2-x_1}}$

are the lines 2x + 5y = 1 and y = 5/2x + 4 parallel, perp, neither, or the same

parallel lines have the same slope, perpendicular lines have slopes that are opposite reciprocals ... not parallel or perpendicular would be neither
...

3. To figure out the slope you use the formula m=y2-y1 / x2-x1 (m being the slop)

So the first points given are (-2,-1) and (5,6)
x1= -2, y1 = -1, x2 = 5 and y2 = 6 now you fill in the blanks of the equation:

6-(-1) divided by 5-(-2) when subtracting a negative you change it to plus a positive so you are left with 7 / 7. The slope is 1.

Now that I have given you the equation maybe you can figure out the second one. Let me know if you need any more help