i need to solve this giving and exact solution... 2e^(x) + 3e^(-x)=7 thanks
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Originally Posted by pop_91 i need to solve this giving and exact solution... 2e^(x) + 3e^(-x)=7 thanks Let $\displaystyle e^x = u $ $\displaystyle 2u + \frac{3}{u} = 7$
Originally Posted by e^(i*pi) Let $\displaystyle e^x = u $ $\displaystyle 2u + \frac{3}{u} = 7$ Further hint: Multiply both sides of the equation by $\displaystyle u$.
major thanks guys
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