Factor 2x^3-98a^2x+28x^2+98x QUESTION: Would it make sense to divide EVERY coefficient in the polynomial by the leading coefficient of 2 to reduce the BIG numbers? Is there an easier method?
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Originally Posted by symmetry Factor 2x^3-98a^2x+28x^2+98x QUESTION: Would it make sense to divide EVERY coefficient in the polynomial by the leading coefficient of 2 to reduce the BIG numbers? Is there an easier method? Yes, you can divide with 2, so you get: I was just wondering, does belong in expression? Is that a typo maybe?
Hello, symmetry! Factor: . Would it make sense to divide EVERY coefficient in the polynomial by the leading coefficient of 2 to reduce the BIG numbers? Well, I wouldn't call it "dividing". You can factor out a . . . it's a factoring problem, remember?
Thank you for your tips. To OReilly: The variable a belongs to the second term. If it is a typo, I would not know. So, what is the final answer?
Hello again, symmetry! If the problem is correctly stated, it's a sneaky one . . . Factor: . Factor out of each term: . We have: . . . . . . . . . . . . a difference of squares! . . . . . . . .
Soroban, I guess the answer to OReilly's question is: Yes, the letter a is part of the question. Thanks!
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