Please help. I have not had algebra for thirty years. How do you solve the following equation?
2^x=2x
Thanks for the help!
2^x = 2x
ln(2^x) = ln(2x)
xln(2) = ln(2) + ln (x)
x = [ln (2) + ln (x)] / ln (2)
x = 1 + ln(x)/ln(2)
From here, by simple inspection, we can see that x can be either 1 or 2.
when x = 1, we have 1 = 1 + ln(1)/ln(2) = 1 + 0
when x = 2, we have 2 = 1 + ln(2)/ln(2) = 1 + 1