Determining slope and y-intercept.

**Rumor** · September 19th 2009, 11:00 AM

So, the equation that I'm given is this:

7y + 12x -2 = 0

and I'm told to determine the y-intercept and the slope of this line, but I'm not entirely sure how to go about doing that.

Any help would be appreciated!

**e^(i*pi)** · September 19th 2009, 11:34 AM

Originally Posted by Rumor

So, the equation that I'm given is this:

7y + 12x -2 = 0

and I'm told to determine the y-intercept and the slope of this line, but I'm not entirely sure how to go about doing that.

Any help would be appreciated!

Manipulate into the form y=mx+c. m is the slope and c is the y-intercept

**fireandice03** · September 19th 2009, 03:34 PM

Originally Posted by Rumor

So, the equation that I'm given is this:

7y + 12x -2 = 0

and I'm told to determine the y-intercept and the slope of this line, but I'm not entirely sure how to go about doing that.

Any help would be appreciated!

If you solve the equation for y in terms of x you will get the equation in slope intercept form.

**Vesicant** · September 20th 2009, 12:43 PM

Originally Posted by Rumor

So, the equation that I'm given is this:

7y + 12x -2 = 0

and I'm told to determine the y-intercept and the slope of this line, but I'm not entirely sure how to go about doing that.

Any help would be appreciated!

$ 7y+12x-2=0 Rearrange into y=mx+b: 7y=-12x+2 Simplify: 7y/7= 12/7x +2/7 y=12/7x + 2/7(0.28) The slope is 12/7 and the y intercept is 0.28.$

**Viral** · September 20th 2009, 01:58 PM

$\begin{array}{rcrcrc} 7y + 12x - 2 = 0\\ 7y = -12x + 2\\ y = \frac{-12x}{7} + \frac{2}{7} \end{array}$

The gradient ( $m$ ) is $\frac{-12x}{7}$ , and the y-intercept ( $c$ ) is $\frac{2}{7}$ .

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