Find the range of values of a for which the following equations have two real roots: x^2 - 2ax + 3a = 0 I've got it down to a^2-3a>0, where do i go from here? Thanks
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The equation $\displaystyle a^2-3a=0$ has the roots $\displaystyle a_1=0, \ a_2=3$ Then $\displaystyle a^2-3a\geq 0$ if $\displaystyle a\in(-\infty,0]\cup[3,\infty)$
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