Discriminant question

**Montydo** · September 19th 2009, 06:38 AM

Find the range of values of a for which the following equations have two real roots:

x^2 - 2ax + 3a = 0

I've got it down to a^2-3a>0, where do i go from here?

Thanks

**red_dog** · September 19th 2009, 06:42 AM

The equation $a^2-3a=0$ has the roots $a_1=0, \ a_2=3$

Then $a^2-3a\geq 0$ if $a\in(-\infty,0]\cup[3,\infty)$

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