# Discriminant question

• Sep 19th 2009, 07:38 AM
Montydo
Discriminant question
Find the range of values of a for which the following equations have two real roots:

x^2 - 2ax + 3a = 0

I've got it down to a^2-3a>0, where do i go from here?

Thanks
• Sep 19th 2009, 07:42 AM
red_dog
The equation $a^2-3a=0$ has the roots $a_1=0, \ a_2=3$

Then $a^2-3a\geq 0$ if $a\in(-\infty,0]\cup[3,\infty)$