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Math Help - Simplifying an expression

  1. #1
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    Simplifying an expression

    the one that is still confusing me is the simplification of:

    Imageshack - 07e3be3572344e492265b64
    Last edited by mr fantastic; September 18th 2009 at 04:35 PM. Reason: Moved form another thread
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  2. #2
    Super Member redsoxfan325's Avatar
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    Quote Originally Posted by frozenflames View Post
    thanks a lot, but i figured that one out.

    the one that is still confusing me is the simplification of:

    Imageshack - 07e3be3572344e492265b64
    \frac{\frac{2}{a+h}-\frac{2}{a}}{h}

    Start by finding common denominators for the two fractions in the numerator and combining them into one fraction:

    \frac{\frac{2}{a+h}-\frac{2}{a}}{h}=\frac{\frac{2a}{a(a+h)}-\frac{2(a+h)}{a(a+h)}}{h} =\frac{\frac{2a-2(a+h)}{a(a+h)}}{h}=\frac{\frac{2a-2a+2h}{a(a+h)}}{h}=\frac{\frac{2h}{a(a+h)}}{h}

    To divide fractions, multiply the top fraction by the reciprocal of the bottom one:

    \frac{\frac{2h}{a(a+h)}}{h}=\frac{2h}{a(a+h)}\cdot  \frac{1}{h}=\frac{2h}{ah(a+h)}

    Cancel the h's and you're done:

    \frac{2h}{ah(a+h)}=\boxed{\frac{2}{a(a+h)}}
    Last edited by mr fantastic; September 18th 2009 at 04:40 PM. Reason: Moved from another thread
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