this is my question: 3 $\displaystyle \frac{1}{5}$ - 1 $\displaystyle \frac{1}{2}$ + 1 $\displaystyle \frac{1}{4}$ im not sure waht to do on it so if you can help please post, thanks
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Originally Posted by andyboy179 this is my question: 3 $\displaystyle \frac{1}{5}$ - 1 $\displaystyle \frac{1}{2}$ + 1 $\displaystyle \frac{1}{4}$ im not sure waht to do on it so if you can help please post, thanks Hi . Write all these fractions as an improper fraction , then make the denominator common . $\displaystyle \frac{16}{5}-\frac{3}{2}+\frac{5}{4}$ $\displaystyle =\frac{16\times4}{5\times4}-\frac{3\times10}{2\times10}+\frac{5\times5}{4\time s5}$
i don't understand the 16 X 4 part, could you go through it a little slower please
Originally Posted by mathaddict Hi . Write all these fractions as an improper fraction , then make the denominator common . $\displaystyle \frac{16}{5}-\frac{3}{2}+\frac{5}{4}$ $\displaystyle =\frac{16\times4}{5\times4}-\frac{3\times10}{2\times10}+\frac{5\times5}{4\time s5}$ ok . I am trying to make all the denominator common ie 20 so for $\displaystyle \frac{16}{5}$ , in order to make its denominator 20 , i will need to take 5 and multiply by 4 , when i multiply the denominator by 4 , i will need to multiply the numerator by 4 as well
oh i understand now, thanks i will do it now then get back to you with the answer
would the answer be, 2 $\displaystyle \frac{19}{20}$
Originally Posted by andyboy179 would the answer be, 2 $\displaystyle \frac{19}{20}$
thanks alot for the help
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