adding and subtracting fractions

**andyboy179** · September 18th 2009, 07:21 AM

this is my question:

3 $\frac{1}{5}$ - 1 $\frac{1}{2}$ + 1 $\frac{1}{4}$

im not sure waht to do on it so if you can help please post, thanks

**mathaddict** · September 18th 2009, 07:34 AM

Originally Posted by andyboy179

this is my question:

3 $\frac{1}{5}$ - 1 $\frac{1}{2}$ + 1 $\frac{1}{4}$

im not sure waht to do on it so if you can help please post, thanks

Hi .

Write all these fractions as an improper fraction , then make the denominator common .

$\frac{16}{5}-\frac{3}{2}+\frac{5}{4}$

$=\frac{16\times4}{5\times4}-\frac{3\times10}{2\times10}+\frac{5\times5}{4\time s5}$

**andyboy179** · September 18th 2009, 07:44 AM

i don't understand the 16 X 4 part, could you go through it a little slower please

**mathaddict** · September 18th 2009, 07:53 AM

Originally Posted by mathaddict

Hi .

Write all these fractions as an improper fraction , then make the denominator common .

$\frac{16}{5}-\frac{3}{2}+\frac{5}{4}$

$=\frac{16\times4}{5\times4}-\frac{3\times10}{2\times10}+\frac{5\times5}{4\time s5}$

ok . I am trying to make all the denominator common ie 20

so for $\frac{16}{5}$ , in order to make its denominator 20 ,

i will need to take 5 and multiply by 4 , when i multiply the denominator by 4 , i will need to multiply the numerator by 4 as well

**andyboy179** · September 18th 2009, 07:55 AM

oh i understand now, thanks i will do it now then get back to you with the answer

**andyboy179** · September 18th 2009, 07:59 AM

would the answer be, 2 $\frac{19}{20}$

**mathaddict** · September 18th 2009, 08:09 AM

Originally Posted by andyboy179

would the answer be, 2 $\frac{19}{20}$

**andyboy179** · September 18th 2009, 08:10 AM

thanks alot for the help

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